x^2-4=7x

Solution for x^2-4=7x equation:

x^2-4=7x

We move all terms to the left:

x^2-4-(7x)=0

a = 1; b = -7; c = -4;
Δ = b2-4ac
Δ = -72-4·1·(-4)
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{65}}{2*1}=\frac{7-\sqrt{65}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{65}}{2*1}=\frac{7+\sqrt{65}}{2}
$